Dental Radiology Radiation Protection Officer Exam Overview
This content discusses a hypothetical exam scenario for a Radiation Protection Officer in dental radiology. It covers topics like equivalent dose rate, skin dose calculation, shielding effectiveness, and dose limits for the environment. Through calculations and evaluations, the exam tests the candidate's understanding of radiation safety measures in a dental practice setting.
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Presentation Transcript
Radiation Protection Officer dental radiology - basic Test exam Frits Pleiter 04/03/2025 03:40 radiation protection officer - thk 1
Question 41 Equivalent dose rate (in mSv per mAs) at a distance of 1 m from the focus. tube voltage thickness aluminum filter 1 mm 2 mm 3 mm 50 kV 0.07 0.05 0.03 70 kV 0.15 0.09 0.05 90 kV 0.20 0.13 0.08 Data: tube voltage filter tube current exposure time distance focus - skin 90 kV 3 mm aluminum 6 mA 0.3 seconds 35 cm Calculate the equivalent skin dose per X-ray photo. 04/03/2025 03:40 radiation protection officer - thk 2
Evaluation of question 41 reading figure A at 90 kV and 3 mm aluminum 0.08 mSv/mAs at 1 meter (1 pt) mAs value = 6 mA 0.3 s = 1.8 mAs (1 pt) equivalent dose at 1 meter = 0,08 mSv/mAs 1.8 mAs = 0.14 mSv (1 pt) equivalent dose at 35 cm = 0.35 m = 0.14 mSv (1 m / 0.35 m)2= 1.2 mSv (1 pt) 04/03/2025 03:40 radiation protection officer - thk 3
Question 42 A dental practice has a single intra-oral X-ray device that is subject to registration. For 50% of the photos, the X-ray beam is directed perpendicular to the double-glass window in the outer wall adjacent to the public road. Data: number of photos per year average tube voltage average mAs value filter distance focus - road thickness double glass the contribution of scatter radiation can be neglected 2000 90 kV 1,5 mAs per photo 3 mm aluminum 3 meters 11 mm Check by means of calculation whether or not the shielding effect of the double glass in the window is sufficient to comply with the dose limit for the environment. 04/03/2025 03:40 radiation protection officer - thk 4
Evaluation of question 42 reading figure A at 90 kV and 3 mm aluminum 0.08 mSv/mAs at 1 meter (1 pt) equivalent dose for 2000 / 2 = 1000 photos 1000 0,08 mSv/mAs 1,5 mAs = 120 mSv at 1 meter equivalent dose at 3 meters = 120 mSv (1 m / 3 m)2= 13 mSv (1 pt) (1 pt) reading figure B at 90 kV and 11 mm glass T = 0.3 annual effective dose on the street = 13 mSv 0.3 = 4 mSv (1 pt) (1 pt) annual limit in case of registration = 10 Sv insufficient shielding (1 pt) 04/03/2025 03:40 radiation protection officer - thk 5
04/03/2025 03:40 radiation protection officer - thk 6
