Digital Communication and Signal Processing Fourier Transform

seminar 3 digital communication and signal n.w
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Explore the concept of Fourier Transform in Digital Communication and Signal Processing, understanding the basis functions, orthogonality, and completeness. Work through exercises to find Fourier Transform functions and key points related to cosine and sine functions. Delve into periodic functions, odd functions, and non-periodic functions within the Fourier Transform context.

  • Digital Communication
  • Signal Processing
  • Fourier Transform
  • Orthogonality
  • Periodic Functions

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  1. Seminar 3 Digital Communication and Signal Processing Fourier Transform Ruohan Zhang Ruohan.Zhang.1@warwick.ac.uk Department of Computer Science, University of Warwick 25/01/2024

  2. FT: Fourier Thm in terms of Sin and Cos simply a generalization of common knowledge of the Euclidean space { 1, cos (n t), sin(nwt), n=1,2 } are orthogonal and complete they form orthogonal bases x(t)= A0+ Ancos(nwt)+ Bnsin(nwt) n=1 n=1 T/2 A0=<1,x(t)>=1 x(t)dt T -T/2 T/2 An=< cos(nwt),x(t)>=2 x(t)cos(nwt)dt T -T/2 T/2 Bn=<sin(nwt),x(t)>=2 x(t)sin(nwt)dt T -T/2 w =2p T where A0is the d.c. term, and T is the period of the waveform.

  3. Exercises Work out the Fourier Transform function of the given ?(?).

  4. Key point: ?? ? d? = 0 ( ? ? is an odd function) 1 a0= 2? ? Periodic function with T = 2 ?? ? cos?d? = 0 ( an odd function times an even function equals an odd function) 1 ? ? a?= ?? ? sin?? d? 1 ? ? ??= k 0 ?sin?? d? + 0 ??sin?? d?) 1 ?( ? = 1 ?[? +[ ? 0 = ?cos??] ? ?cos??]0 - 0 2 -2 1 ?[? ? ?cos ?? + ( ? ? ?)] = ? ?cos ?? ) ( -k 1 ?[? ? ?cos ?? ? ?cos ?? ) +? = ? ?] 4? ?? ? ?? ? ?? ??? = 0 ? ?? ? ?? ???? 4? ?(sin? + 1 3sin3? + 1 5sin5? + ) ? ? =

  5. 2?(?)d? = 1 1?d? = 1 4 2 1 4[??] 1 ? 2 Key point: 1= ?0= 4 1 Periodic function with T = 4 2 2 2 4 ?(?)cos?2? 2 4 ?(?)sin?2? ??= 4?d? ??= 4?d? 2 2 1 1 1 2 ? cos?? 1 2 ? sin?? = 2? d? = 2?d? k 1 1 1 2[2? ??sin?? 1 2[ 2? ??cos?? 1 = 2?] 1 1 = 2?] 1 -1 0 2 1 -2 1 2 2? ??[sin?? 2 sin( ?? = 1 2 2? ??[cos?? 2 cos( ?? = 2)] 2)] -k 2? ??sin?? = 0 = 2 ? 2+ 2? ?(cos? 2? 1 3cos3? 2? +1 5cos5? ? ? = 2? + )

  6. Key point: + ?(?)? 2????d? ? ? = ?? ? = Non-periodic function 1 ? 2?. In the general Fourier Transform formula, ? = ? 2????d? = 1 Here, ? represents frequency and ? represents angular velocity. ? ?? ? 0 ? ?? ? = 0 1 1 ?(?) = [ ? 2???? ? ? = d? = 2 1 2???] 1 1 -1 0 2 1 -2 ?2??? ? 2??? 2??? = -k

  7. Knowledge point expansion: We can also use another form of Fourier Transform formula (using ? as an integral variable). Here, ? represents frequency and ? represents angular velocity. ? ? ? ???d? ? ? = ?? ? = 1 ? ? = ?? 1? = ?(?)????d? 2?

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