Ester Hydrolysis in Acidic Media - Procedure and Kinetics
"Learn about the procedure and kinetics of ester hydrolysis in acidic media, including the theory behind the reaction and how to determine the rate of reaction. Follow a step-by-step guide and analyze the results to calculate the rate constant."
Download Presentation
Please find below an Image/Link to download the presentation.
The content on the website is provided AS IS for your information and personal use only. It may not be sold, licensed, or shared on other websites without obtaining consent from the author. If you encounter any issues during the download, it is possible that the publisher has removed the file from their server.
You are allowed to download the files provided on this website for personal or commercial use, subject to the condition that they are used lawfully. All files are the property of their respective owners.
The content on the website is provided AS IS for your information and personal use only. It may not be sold, licensed, or shared on other websites without obtaining consent from the author.
E N D
Presentation Transcript
Ester Hydrolysis in Acidic Media Muaathe A Ibraheem
Theory For particle reasons this reaction is chosen .The rate of acidic hydrolysis of Esters is relatively slow, so that it can be determined in observable scale time. Moreover, As the reaction catalysis by acidic solution, then the product can be check out directly by following the mount of acid release. Simple titration of a taken portion (aliquots) against NaOH solution is recommended In case the taken portion is diluted, this likely will stop the reaction which give enough time to get more accurate results
?+ ??3?????3+ ?2? If we use water in access the rate of reaction is determine by concentration of the Ester only So the rate of reaction constant k can be given by ??3???? + ??3?? ? =2.303 ? ??? ? ? (1) ? Where a is the initial concentration of the ester. a-x is the remain amount of it.
Procedure In a beaker mix 100ml 0f 0.1M HCl and 5 ml of methyl acetate After 5 min take 10 ml from the mixture and add 20 ml of cold distilled water titrate against 0.05M NaOH solution (use Ph.Ph. As indicator). The equivalent volume of the NaOH represents the Vt A 10 ml of the mixture is taken from the beginning and heated at 50C for 60 min then it will titrate with NaOH solution as the former step. The titrate volume will be ? Arrange the results as the table below
3 ln(? ??) ? Time min Vt 2.5 2 5 Slope= -k ln V -Vt 10 1.5 y = -0.0964x + 3.0551 R = 1 15 1 20 0.5 25 0 0 5 10 15 20 25 30 35 t min Draw the result as in the graph and determine the K value from the slop
