L5 Velocity time graphs

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This educational content focuses on interpreting distance-time graphs and understanding concepts related to speed, acceleration, and velocity in the context of motion analysis. Students will enhance their knowledge through practical applications and equations of motion, preparing them for advanced learning objectives in the future. The lesson sequence emphasizes interpreting graphs, calculating acceleration, and understanding the relationship between speed, time, and distance travelled.

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Uploaded on Feb 17, 2025 | 0 Views

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L1 Speed L2 Distance-time graphs L3 Speed practical L4 Acceleration L5 Velocity time graphs L6 Equation of motion Lesson Sequence Pupils should have been taught to: Pupils will be taught: Interpret distance-time graphs; knowledge of gradients should be relied upon & revisited during this lesson. Lesson on equation of motion can revisit the ideas taught in this lesson. Future Learning Specification Prior Learning

SciDoc Velocity Velocity- -time graphs time graphs 17/02/2025 Last Lesson Last Term Last Year Stretch & Challenge I do We do You do Test I do We do You do Do Now

SciDoc Velocity Velocity- -time graphs time graphs Keywords Learning Objectives Keywords Acceleration Speed Velocity Time Gradient Describe how to obtain acceleration from a velocity-time graph. Describe how to obtain distance travelled from a velocity-time graph. Calculate accelerations and distances travelled from a velocity-time graph. I do We do You do Test I do We do You do Do Now

0 5 10 15 20 25 30 35 40 45 50 Time/Seconds 0 5 10 15 20 25 30 35 40 45 50 55 Speed/m/s 0 SciDoc 6 16 26 30 30 30 30 20 10 0 0 Speed (m/s) I do We do You do 0 10 20 30 40 50 60 70 80 Test I do We do You do LO: Time (s)

Stretch: Calculate the acceleration from the SciDoc gradient of the graph. Velocity Velocity- -time graphs time graphs Diagonally Up Constant Acceleration Horizontal Constant speed Diagonally Down Constant Deceleration Gradient This is the acceleration of the object. Area under the graph This is the distance travelled by the object. Calculate the distance travelled from the area under the graph. I do We do You do Test I do We do You do LO:

12 12 12 12 SciDoc 10 10 10 10 Accelerating accel 8 8 8 8 = 10 = 2.5 m/s2 Velocity (m/s) 4 6 6 6 6 10 Distance = area 4 4 4 4 = x 4 x 10 = 20 m 2 2 2 2 4 0 0 0 0 -2 -2 -2 -2 0 0 0 0 2 2 2 2 4 4 4 4 6 6 6 6 8 8 8 8 10 10 10 10 12 12 12 12 14 14 14 14 16 16 16 16 18 18 18 18 Time (s) -2 -2 -2 -2 I do We do You do Test I do We do You do LO: 6

12 12 12 12 SciDoc 10 10 10 10 6 8 8 8 8 Decelerating decel Velocity (m/s) = 9 = 1.5 m/s2 6 6 6 6 6 9 4 4 4 4 Distance = area = x 6 x 9 = 27 m 2 2 2 2 0 0 0 0 -2 -2 -2 -2 0 0 0 0 2 2 2 2 4 4 4 4 6 6 6 6 8 8 8 8 10 10 10 10 12 12 12 12 14 14 14 14 16 16 16 16 18 18 18 18 Time (s) -2 -2 -2 -2 I do We do You do Test I do We do You do LO: 7

12 12 12 12 Constant speed of 6 m/s for 6 seconds, then decelerating SciDoc 10 10 10 10 Distance = area = 6 = 2 m/s2 decel 3 =( x 3 x 6) + 6 x 6 = 45 m 8 8 8 8 Velocity (m/s) 3 6 6 6 6 4 4 4 4 6 2 2 2 2 0 0 0 0 -2 -2 -2 -2 0 0 0 0 2 2 2 2 4 4 4 4 6 6 6 6 8 8 8 8 10 10 10 10 12 12 12 12 14 14 14 14 16 16 16 16 18 18 18 18 Time (s) -2 -2 -2 -2 I do We do You do Test I do We do You do LO:

SciDoc Worksheet Worksheet Complete the worksheet I do We do You do Test I do We do You do LO:

SciDoc Basic answers Basic answers I do We do You do Test I do We do You do LO:

SciDoc Medium answers Medium answers acceleration = 0.5 m/s2 distance = 25m acceleration = 0.5 m/s2 distance = 16m acceleration = 0.9 m/s2 distance = 45m acceleration = -1 m/s2 distance = 30m acceleration = -1 m/s2 distance = 8m acceleration = -0.25 m/s2 distance = 8m I do We do You do Test I do We do You do LO:

SciDoc Hard answers Hard answers distance = 52m distance = 40m distance = 32m distance = 55m distance = 23m distance = 38m I do We do You do Test I do We do You do LO: