Optimizing FFT Analysis for ADS8320EVM-PDK SNR Measurements
Explore how to optimize FFT analysis for the ADS8320EVM-PDK to achieve accurate signal-to-noise ratio measurements. Learn about hardware setup, verified sampling rates, and adjusting FFT parameters for more precise AC analysis using the provided images and information.
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Presentation Transcript
ADS8320EVM-PDK SNR Measurements 11/01/21 1 TI Information Selective Disclosure
EVM hardware setup Jumper Setting JMP1 [1-2] JMP2 [1-2] JMP3 [5-6] JMP4 [1-2] JMP5 [1-2] JMP6 [1-2] 2 TI Information Selective Disclosure
Verified sampling rate 3 TI Information Selective Disclosure
FFT results FFT bin size calculated based on displayed Sample Rate 2.4 MHz / 131,072 bins = 18.3 Hz / bin Adjust FFT bins parameters for more accurate AC analysis -20 dBFS input IN+ = 250 mVpp, 1.25 V offset IN- = AGND R1 = R4 = 0 , C4 = open 4 TI Information Selective Disclosure
FFT results FFT bin size calculated based on displayed Sample Rate 2.4 MHz / 131,072 bins = 18.3 Hz / bin Adjust FFT bins parameters for more accurate AC analysis -0.5 dBFS input IN+ = 2.36 Vpp, 1.25 V offset IN- = AGND R1 = R4 = 0 , C4 = open 5 TI Information Selective Disclosure
FFT results FFT bin size calculated based on displayed Sample Rate 2.4 MHz / 131,072 bins = 18.3 Hz / bin Adjust FFT bins parameters for more accurate AC analysis -0.5 dBFS input IN+ = 2.36 Vpp, 1.25 V offset IN- = AGND R1 = R4 = 100 , C4 = 820 pF 6 TI Information Selective Disclosure
FFT results FFT bin size calculated based on displayed Sample Rate 2.4 MHz / 131,072 bins = 18.3 Hz / bin Adjust FFT bins parameters for more accurate AC analysis -0.5 dBFS input pre-amp board IN+ = 2.36 Vpp, 1.25 V offset IN- = AGND R1 = R4 = 100 , C4 = 820 pF C2 = C3 = 100 pF 7 TI Information Selective Disclosure
FFT results FFT bin size calculated based on displayed Sample Rate 2.4 MHz / 131,072 bins = 18.3 Hz / bin Adjust FFT bins parameters for more accurate AC analysis -0.5 dBFS input pre-amp board IN+ = 2.36 Vpp, 1.25 V offset IN- = AGND R1 = R4 = 100 , C4 = 10 nF C2 = C3 = 100 pF 8 TI Information Selective Disclosure
