Potential Energy: Gravitational and Spring Energies

Potential Energy: Gravitational and Spring Energies
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Discover the concepts of potential energy through examples including gravitational potential energy, conservation of energy, roller coaster dynamics, pendulum behavior, and spring potential energy. Explore how potential energy transforms into kinetic energy in various scenarios, providing insights into the fundamental principles of physics and energy conservation.

  • Potential Energy
  • Gravitational Energy
  • Conservation
  • Examples
  • Physics

Uploaded on Mar 14, 2025 | 0 Views


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  1. Chapter 7 POTENTIAL ENERGY

  2. GRAVITATIONAL POTENTIAL ENERGY PE = mgh The higher you are, the more energy you have.

  3. CONSERVATION OF ENERGY

  4. CONSERVATION OF ENERGY (NO FRICTION) KE1+ PE1= KE2+ PE2

  5. CONSERVATION OF ENERGY What is the speed v of the ball at the bottom if the ball is released from rest? PEi= mgh, KEi= 0 PEf= 0, KEf=1 Ei= Ef PEi+ KEi= PEf+ KEf mgh + 0 = 0 +1 2mv2 2mv2 mgh =1 h 2mv2 2gh v =

  6. EXAMPLE 2 If the ball is initially travelling at v0, what is the speed v of the ball when it is at h/3? Ei= Ef PEi+ KEi= PEf+ KEf mgh +1 PEi= mgh, KEi=1 PEf= mg(h 2 2mv0 2mv2 3), KEf=1 2=1 3mgh +1 2=1 2mv2 2mv2 2mv0 2 3mgh +1 2mv0 h 2+4 v = v0 3gh h/3

  7. FIND THE FINAL SPEED PEi= mgh,KEi=1 2 2mv0 mgh +1 2=1 2mv2 2mv0 2+ 2gh v2= v0 v = 35.8m / s PEf= 0,KEf=1 2mv2

  8. ROLLER COASTER A roller coaster slides down a frictionless track at height h with initial speed v0. Find the speed at A. PEi= mgh, KEi=1 PEf= mg(2R), KEf=1 Ei= Ef PEi+ KEi= PEf+ KEf mgh +1 2mv0 1 2mv0 v = v0 2 2mv0 2mv2 2= 2mgR +1 2mv2 2mv2=1 2+ mg(h - 2R) 2+ 2g(h - 2R)

  9. PENDULUM Given m= 20kg,q = 20 ,L =1.5m, find the PE of the pendulum. The PE of the pendulum is mgh, but what is h? h + Lcosq = L h = L(1-cosq) = 0.0905m PE = mgh = mgL(1-cosq)=17.7J Lcosq h

  10. POTENTIAL ENERGY IN A SPRING PEs=1 2kx2 k : spring constant [N /m] x : extension [m]

  11. HOW FAST WILL IT GO? Given m=2kg, k =1.5N /m, x = -0.2m, find the speed v when the object left the spring. PEi=1 2kx2,KEi= 0 PEf= 0,KEf=1 2mv2 1 2kx2=1 2mv2 kx2 m v = = 0.17m/s

  12. WF WORK DONE BY FRICTION (NON-CONSERVATIVE FORCE) KEi+ PEi+Wfriction= KEf+ PEf DE = Ef- Ei=DKE + DPE =Wfriction Remember Wf 0!!!

  13. TWO POTENTIAL ENERGY? Later in Chapter 11, we will learn another equation for gravitational potential energy: PE = -GMm r The differecen between PE = mgh and PE = -GMm r PEG=mghis only true near the planet s surface (where g is a constant). Far away the gravitational field gets weak (where g gets smaller) and PEG=mghis no longer true.

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