Preparation and Standardization of 0.1N Hydrochloric Acid
This experiment involves the preparation and standardization of 0.1N hydrochloric acid using standard sodium carbonate. Detailed steps include preparing solutions, dilution calculations, and the procedure using methyl orange indicator. The equivalence point calculation is also outlined for determining the milliequivalents of HCl and Na2CO3.
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Presentation Transcript
Experiment No. 1 Preparation and standardization of 0.1N hydrochloric acid (HCl) by using standard sodium carbonate (Na2CO3)
Hydrochloric acid (HCl) is not standard substance; therefore it must be standardized by using standard sodium carbonate (Na2CO3). Na2CO3 + 2 HCl 2 NaCl + H2CO3 2 NaCl + CO2 + H2O
Preparation of solutions 1- Prepare 0.1N Na2CO3 in 250mL of distilled water Na2CO3 is a solid substance. N eq.wt V (ml) F.wt of Na2CO3 2 1 Wt = eq.wt = 1000 2 23 + 1 12 + 3 16 0.1 53 250 eq.wt = Wt = 2 1000 106 = 53 g/mol eq.wt = 2 Wt = 1.325 g Dissolve 1.325 g Na2CO3 in 250 ml of distilled water to obtain 0.1N Na2CO3.
2- Prepare 0.1N HCl in 250mL of distilled water HClis a liquid substance. Sp.gr = 1.19 %HCl = 37% Sp.gr % 1000 F.wt of HCl eq.wt = N = 1 eq.wt 1 1 + 1 35.5 37 100 1000 eq.wt = 1.19 1 N = 36.5 eq.wt = 36.5 g/mol N = 12 eq/L
no. of milliequivalence after dilution no. of milliequivalence before dilution = (N2 V2)dilu. (N1 V1)conc.= 12 V1 = 0.1 250 0.1 250 12 = 2.08 ml = 2.1 ml V1= Take 2.1 ml of concentrated HCl with a pipet, and dilute to 250 ml with distilled water in a 250ml-volumetric flask to obtain approximately 0.1 N HCl.
Procedure: 10ml of HCl (0.1N) 0.1 N Na2CO3solution 2-3 drops of methyl orange 10 ml of HCl solution 2 drops of methyl orange The Colour changed from Red - to - yelow (1) (2) (3)
Calculation At the equivalence point no. of milliequivalence of HCl no. of milliequivalence of Na2CO3= (N1 V1) Na2CO3= (N2 V2)HCl 0.1 Vaverage = N2 10 0.1 Vaverage 10 = ( ) eq/L HCl N2=
