Solving Physics Problems with Newton's Laws
Explore how to solve physics problems using Newton's laws with practical examples such as calculating depths of wells and distances traveled by cars under various conditions. Enhance your understanding of forces through extended problems and apply the SUVAT model for moving objects.
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Presentation Transcript
Forces 2ndLaw and suvat Extended problems
KUS objectives BAT Understand Newtons 3 laws BAT Solve problems using Newtons 2nd law BAT solve problems with moving objects using the suvat model Starter:
WB9 A stone of mass 0.5 kg is released from rest on the surface of the water in the well. Suggest a model i) The stone is modelled as a particle ii) acceleration g is constant iii) resistance force due to the water is constant iv)There are no other forces A stone of mass 0.5 kg is released from rest on the surface of the water in the well. It takes 2 seconds to reach the bottom of the well. Given that the water exerts a constant resistance of 2 N, find the depth of the well
WB9solution A stone of mass 0.5 kg is released from rest on the surface of the water in the well. It takes 2 seconds to reach the bottom of the well. Given that the water exerts a constant resistance of 2 N, find the depth of the well s R Draw a diagram: = 0 u a v = 8 . 5 a W = 2 t F = R ma 5 . 0 = = + 2 2nd Law s ut 1at 2 W a = + 8 . 5 2 0 2 s 1 2 8 . 9 5 . 0 = 5 . 0 2 a = 11 6 . s m = 2 8 . 5 a ms
WB10 Car A car travels a distance of 32m along a straight road while uniformly accelerating from rest to 16 ms-1. By modelling the car as a particle find its acceleration. Given that the mass of the car is 640 Kg, find the magnitude of the accelerating force. = F = 32 s ma = + 2 2 2 v u as = 0 u = 640 = + 4 2 2 F 16 0 2 32 a = 16 v = 2 4 a ms = = a 2560 F N = t
WB11 A car of mass 500 kg travelling at a constant speed of 25 ms-1 reaches a slope inclined at 300 to the horizontal. The resistance forces on the car travelling up the slope total 300 N. The driver takes their foot off the acceleration pedal at the start of the slope Find the distance travelled by the car before it comes to rest R = = 500g cos 30 R 300 Resultant Force down slope 30 sin 500 + g 30 = = 300 2750 F 500g g F = ma = s 2750 = 500 a = 25 u = 625 + + 2 2 2 2 v 0 u as 5 . 5 = a deceleration = 0 v = ( ) 5 . 5 s = 5 . 5 a = 56 8 . s m = t
KUS objectives Understand Newtons 3 laws Solve problems using Newtons 2nd law solve problems with moving objects using suvat model self-assess One thing learned is One thing to improve is
