
Subnetting Exercises for Networking and Communication Systems Department
Practice subnetting exercises for network administrators. Learn how to create multiple subnets within an IP address block, determine subnet masks, calculate the number of addresses in each subnet, and find the first and last addresses in a subnet.
Download Presentation

Please find below an Image/Link to download the presentation.
The content on the website is provided AS IS for your information and personal use only. It may not be sold, licensed, or shared on other websites without obtaining consent from the author. If you encounter any issues during the download, it is possible that the publisher has removed the file from their server.
You are allowed to download the files provided on this website for personal or commercial use, subject to the condition that they are used lawfully. All files are the property of their respective owners.
The content on the website is provided AS IS for your information and personal use only. It may not be sold, licensed, or shared on other websites without obtaining consent from the author.
E N D
Presentation Transcript
1 NET 323 NETWORKS PROTOCOLS Networks and Communication Systems Department Subnetting Exercises
Question # 1 2 An organization is granted the block 211.17.180.0/24. The administrator wants to create 32 subnets. 1. Find the subnet mask. 2. Find the number of address in each subnet 3. Find the first and last address in subnet 1 Networks and Communication Systems Department
Answer 3 1. Find the subnet mask. Number of extra 1s =???2 32 = 5 Subnet Mask: /29 (24 + 5) 2. Find the number of address in each subnet Number of addresses = 232 29 = 23 = 8 addresses per subnet Networks and Communication Systems Department
Answer cont. 4 3. Find the first and last address in subnet 1 Networks and Communication Systems Department
Question # 2 5 An organization is granted a block of addresses 192.168.1.0/24. The organization has three branches and needs to divide the addresses into three subnets (each subnet has 6 hosts) Find the subnet mask, subnet and broadcast address for each subnet. Networks and Communication Systems Department
Answer 6 Subnet mask for the three subnets: # of address= 232 ? 8 = 232 ? 23 = 232 ? 3= 32-n n= 32-3 = 29 Subnet mask = /29 # of address in each subnet = 23= 8 Networks and Communication Systems Department
Answer cont. 7 Subnet # Subnet address Broadcast address 192.168.1.7 192.168.1.15 192.168.1.23 hosts 1 2 3 192.168,1.0/29 192.168,1.8/29 192.168,1.16/29 192.168.1.1- 191.168.1.6 192.168.1.9- 191.168.1.14 192.168.1.17- 191.168.1.22 Networks and Communication Systems Department
Question # 3 8 An organization is granted a block of addresses 208.3.30.0/24 The organization has three offices and needs to divide the addresses into three subnets and each subnet has 10 hosts. Find the subnet mask, subnet and broadcast address for each subnet. Networks and Communication Systems Department
Answer 9 Subnet mask for the three subnets: # of address= 232 ? 16 = 232 ? 24 = 232 ? 4= 32-n n= 32-4 = 28 Subnet mask = /28 # of address in each subnet = 2?= 16 Networks and Communication Systems Department
Answer cont. 10 Subnet # Subnet address Broadcast address 208.3.30.15 208.3.30.31 208.3.30.47 hosts 1 2 3 208.3.30.0/28 208.3.30.16/28 208.3.30.32/28 208.3.30.1 - 208.3.30.14 208.3.30.17 - 208.3.30.30 208.3.30.33 - 208.3.30.46 Networks and Communication Systems Department
Question # 4 11 An organization is granted a block of addresses 200.3.2.0/24 The organization has three offices in different cities and needs to divide the addresses into three subnets as the following table: City Riyadh Jeddah Dammam Number of hosts 40 10 6 Find the subnet mask, the subnet and broadcast address for each subnet. Networks and Communication Systems Department
Answer 12 Riyadh Subnet mask for the Riyadh subnet # of address= 232 ? 64 = 232 ? 26 = 232 ? 6= 32-n n= 32-6 = 26 Subnet mask = /26 # of address in Riyadh subnet = 2?= 64 Networks and Communication Systems Department
Answer cont. 13 Jeddah Subnet mask for the Jeddah subnet # of address= 232 ? 16 = 232 ? 24 = 232 ? 4= 32-n n= 32-4 = 28 Subnet mask = /28 # of address in Jeddah subnet = 2?= 16 Networks and Communication Systems Department
Answer cont. 14 Dammam Subnet mask for the Dammam subnet # of address= 232 ? 8 = 232 ? 23 = 232 ? 3= 32-n n= 32-3 = 29 Subnet mask = /29 # of address in Dammam subnet = 23= 8 Networks and Communication Systems Department
Answer cont. 15 Subnet # Subnet address Broadcast address 200.3.2.63 200.3.2.79 200.3.2.87 hosts Riyadh Jeddah Dammam 200.3.2.80/29 200.3.2.0/26 200.3.2.64/28 200.3.2.1 -200.3.2.62 200.3.2.65 - 200.3.2.78 200.3.2.81 - 200.3.2.86 Networks and Communication Systems Department