Understanding Resistive Circuits: Ohm's Law, Power Calculation, and Examples

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Dive into the world of resistive circuits with this comprehensive guide covering Ohm's Law, instantaneous power calculation, conductance, open and short circuits, and practical examples to enhance your understanding.

  • Resistive Circuits
  • Ohms Law
  • Power Calculation
  • Conductance
  • Circuit Examples

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  1. Ministry of Higher Education and Scientific Research Al-Mustansiriyah University Faculty of Engineering Computer Engineering Department Electrical Eng. Lab 1' class Assistant Assistant Lecturer Lecturer Hazim alkargole 2017 20189

  2. CHAPTER 2 RESISTIVE CIRCUITS Ohm s law : The voltage across a resistor is directly proportional to the current flowing through it. v (t) V (t) = R i(t) The symbol of ohm is ( ) R 0 R 1 i(t) 1 =1V 1A

  3. THE INSTANTANEOUS POWER P (T): P(t) = v(t) i(t) = R i(t)i(t) v(t) v2 (t) R = R i (t) = v(t) = 2 R v2 (t) P(t) = v(t) i(t) = R i (t) = 2 R Note: Last equation says that the power at a resistor isalways positive Resistors always absorb power. The inverse of resistance is conductance G =1 R

  4. THE UNIT OF CONDUCTANCE IS SIEMENS(S) 1S =1A 1V The current can be also expressedas i(t)=GV(t) And the instantaneous power is i2(t) i(t) P(t)=v(t)i(t)= i(t)= G G

  5. P(t) = v(t) i(t) = v(t) G v(t) = G v 2(t) i2 (t) = v(t)i(t) = = Gv 2 (t) G Open and short Circuits Open circuit ( R = ) G = 0 R= Open circuit circuit circuit i(t)=v(t)=v(t)=0 R

  6. G = Short circuit ( R = 0) Short circuit circuit circuit R= 0 v(t)= Ri(t)= 0*i(t) = 0

  7. I EXAMPLE : CONSIDER THE CIRCUIT: R = 2 k vs=12 v + - Find the current and power absorbed by theresistor I =vs =12v=6mA R 2k P=vRI=(12)(6m)=72mw

  8. EXAMPL E: The power absorbed by a 10 k resistor in the circuit is 3.6 mW. I Find voltage and current in the resistor. P=V I =I2 R s I2 =P R=10k + - vs R P= (3.6*10 3)(10*103) I= R I= 3.6*10 7=0.6mA V=IR=(0.6mA)(10k ) V=6V

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