
Understanding Resistive Circuits: Ohm's Law, Power Calculation, and Examples
Dive into the world of resistive circuits with this comprehensive guide covering Ohm's Law, instantaneous power calculation, conductance, open and short circuits, and practical examples to enhance your understanding.
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Ministry of Higher Education and Scientific Research Al-Mustansiriyah University Faculty of Engineering Computer Engineering Department Electrical Eng. Lab 1' class Assistant Assistant Lecturer Lecturer Hazim alkargole 2017 20189
CHAPTER 2 RESISTIVE CIRCUITS Ohm s law : The voltage across a resistor is directly proportional to the current flowing through it. v (t) V (t) = R i(t) The symbol of ohm is ( ) R 0 R 1 i(t) 1 =1V 1A
THE INSTANTANEOUS POWER P (T): P(t) = v(t) i(t) = R i(t)i(t) v(t) v2 (t) R = R i (t) = v(t) = 2 R v2 (t) P(t) = v(t) i(t) = R i (t) = 2 R Note: Last equation says that the power at a resistor isalways positive Resistors always absorb power. The inverse of resistance is conductance G =1 R
THE UNIT OF CONDUCTANCE IS SIEMENS(S) 1S =1A 1V The current can be also expressedas i(t)=GV(t) And the instantaneous power is i2(t) i(t) P(t)=v(t)i(t)= i(t)= G G
P(t) = v(t) i(t) = v(t) G v(t) = G v 2(t) i2 (t) = v(t)i(t) = = Gv 2 (t) G Open and short Circuits Open circuit ( R = ) G = 0 R= Open circuit circuit circuit i(t)=v(t)=v(t)=0 R
G = Short circuit ( R = 0) Short circuit circuit circuit R= 0 v(t)= Ri(t)= 0*i(t) = 0
I EXAMPLE : CONSIDER THE CIRCUIT: R = 2 k vs=12 v + - Find the current and power absorbed by theresistor I =vs =12v=6mA R 2k P=vRI=(12)(6m)=72mw
EXAMPL E: The power absorbed by a 10 k resistor in the circuit is 3.6 mW. I Find voltage and current in the resistor. P=V I =I2 R s I2 =P R=10k + - vs R P= (3.6*10 3)(10*103) I= R I= 3.6*10 7=0.6mA V=IR=(0.6mA)(10k ) V=6V