Volume, Mass, and Concentration in Life Science
Dive into the concepts of volume, mass, and concentration in life science with this post-test. Learn about measuring mass, determining volume, understanding concentration, and more through a series of questions and images.
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Life Science Water s the Matter Measuring Mass Post-Test
1. Volume is best described as ____________. A. How much an object weighs B. How much matter is dissolved in water C. How much matter is in an object D. How much space an object occupies E. How fast an object is moving
2. The mass of an object is dependent upon its ____________. A. Gravity B. Volume C. Matter D. Heat E. Energy
3. Which of the following statements concerning concentration is true? A. Concentration is equal to gravity times mass B. Concentration is how much matter is in a given volume C. Concentration is equal to matter times volume D. Concentration is how much mass is present at a given gravity E. Concentration is equal to gravity times volume
4. In order to determine concentration, you would need to know ________ and ________. A. mass; volume B. mass; gravity C. volume; gravity D. volume; weight E. mass; weight
5. Using the metric system, volume is often measured in units of _______. A. Grams B. Liters C. Grams/Liter D. Ounces E. Pounds
6. Which of the following methods could you use to measure the mass of an object? A. Placing it on a balance B. Placing it in a beaker C. Measuring it with a ruler D. Immersing it in water E. Using a thermometer
7. Which of the following solutions would have the lowest concentration of sugar A. One gram of sugar in one liter B. One milligram of sugar in one milliliter C. One kilogram of sugar in one milliliter D. One gram of sugar in one milliliter E. One milligram of sugar in one liter
Post-Test Question # 7 1 g sugar 1000 mL water 1 mg sugar 1 g sugar a) b) = 1 g/L = 1 g/L 1 L water 1000 mg sugar 1 L water 1 mL water 1000 mL water 1 kg sugar 1 g sugar 1000 g sugar c) = 1000 g/L d) = 1000 g/L 1 mL water 1 L water 1 kg sugar 1 L water 1 g sugar 1 mg sugar e) = 0.001 g/L 1 L water 1000 mg sugar
8. If gravity were to no longer present, an object would no longer have ______ . A. Volume B. Mass C. Size D. Weight E. Concentration
9. Which of the following is a measure of mass in the metric system? A. Kilograms B. Liters C. Pints D. Ounces E. Pounds
10. Kelly is treating a small fishpond with a chemical to neutralize pesticide contamination. To be effective, the concentration of the chemical needs to be 3 g of chemical in 1 liter of volume. If Kelly has 100 g of the chemical, how much pond water can she treat? A. 300 mL B. 333 mL C. 3.33 L D. 33.3 L E. 300 L
Post-Test Question # 10 c = 3 mg/L m = 100 g V = ? c = m/V 100 g chem 1 L = 33.3 L 3 g chem
11. Ali is treating a small fishpond with a chemical to neutralize pesticide contamination. To be effective, the concentration of the chemical needs to be 3 mg of chemical in 1 liter of volume. If he wants to treat 1500 L of pond water does Ali need to add? A. 45 mg B. 4.5 g C. 45 g D. 50 g E. 500 g
Post-Test Question # 11 c = 3 mg/L m = ? V = 1500 L c = m/V 1500 L 3 mg chem 1 g chem = 4.5 g chem 1000 mg chem 1 L
12. Isabelle is treating a small fishpond with a chemical to neutralize pesticide contamination. To be effective, the concentration of the chemical needs to be 3 mg of chemical in 1 liter of volume. Unfortunately, Isabelle was distracted while treating the 1000-liter pond and ended up adding too much chemical. She measures the concentration to be 8 mg of chemical in 1 liter. How much of the chemical did Isabelle add? A. 8 mg B. 80 mg C. 8 g D. 80 g E. 8 kg
Pre-Test Question # 12 c = 8 mg/L m = ? V = 1000 L c = m/V 1000 L 8 mg chem 1 g chem = 8 g chemical 1000 mg chem 1 L
13. Isabelles little brother decides that he, too, can treat pond water. He dumps 100 g of sugar in 500 L of pond water. If Isabelle were to measure the concentration of her brother s creation, what would it be? A. 0.1 mg/L B. 0.2 mg/L C. 1 mg/L D. 0.2 g/L E. 1 g/L
Post-Test Question # 13 c = ? m = 100 g sugar V = 500 L pond water c = m/V 100 g sugar = 0.2 g/L 500 L water
