Water Resources Management Principles in Environmental Engineering
Explore the principles of water resources management in environmental engineering, focusing on spillway design and velocity calculations. Learn about spillway rating curves and theoretical vs. actual velocities for efficient water flow control.
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Presentation Transcript
PRINCIPALS OF WATER RESOURCES MANAR BANWAN HASAN 3RDCLASS ENVIRONMENTAL ENGINEERING DEPARTMENT
SPILLWAY The flow rate (rating curve), at the following stages (H = 2 , 4 , 6 , 8 , 10). Considering that the design head is 9 m and the height of the spillway p = 20 mwith 100m long. Sketch the curve Theoretical and actual velocity at the toe point for the design head
SPILLWAY GIVEN HD = 9 M , P = 20 M , L = 100 M SO, G = 9.81 M/S2 SOLUTION ? ??=?? ? ??= ?= ?.??? > 1.33 ?? ??= ? AND H=HE ANY WHERE ?? = ? = ? ?? ? ???.?= ? ?? ? ??.? WITH L = 100 & G = 9.81 ? = ? ? ?.?? ??? ??.?= ???.??? ? ??.? WHERE H IN M & Q IN M3/S NOW FOR CD ( C AT H = HD=9 M)
SPILLWAY ? ??=?? ? ???? ?= ?.???YIELDS THAT CD = 0.4905 FROM THE CHART ??= TO FIND THE DISCHARGE OVER THE SPILLWAY AT THE REQUIRED HEADS WE MUST FIND THE VALUES OF C AT THAT HEADS AND AS FOLLOWS: ? = ???.??? ???.? (m3/s) ? ?? ? H C ?? 522.308 2 0.22 0.85 0.4169 1564.482 4 0.44 0.9 0.4415 3027.120 6 0.67 0.948 0.465 4817.912 8 0.89 0.98 0.4807 6939.142 10 1.11 1.01 0.4954
Q-H Spillway Rating Curve 8000 7000 Q = 170.2H1.607 6000 5000 Q in m3/s 4000 3000 2000 1000 0 0 1 2 3 4 5 6 7 8 9 10 11 12 H in m
SPILLWAY FOR THEORETICAL VELOCITY (VTH):- FROM THE FIG.1 ES = P + HD = 20 + 9 = 29 M ALSO, ?? = ? +?? ?? ????= ? + ?? ??= ? + ??(? ?)? FOR H = HD =9 M THE DISCHARGE Q IS: ? = ? ?? ? ???.?= ?? ?? ? ???.? ? = ?.???? ? ?.?? ??? (?)?.?= 5866.138 ?3/S
SPILLWAY ?2 ? ? ???????? ?????? ?? = ? + 2?(? ?)2 ???? ?? (5866.138)2 2 9.81(? 100)2 29 = ? + 29 = ? +175.39 ?2
SPILLWAY FOR ACTUAL VELOCITY (VA):- THE ACTUAL VELOCITY SHOULD BE CALCULATED FROM THE CHART (FIG.13) AS FOLLOWS: Z = H + P = 9 + 20 = 29 M NOTE THAT (Z & H) SHOULD BE IN FT ? = ?? ? = ??.?? ?? & ? = 9 ? = 29.528 ?? SO; FROM THE FIG.13, WITH Z = 95.14 FT AND H = 29.528 FT THE ACTUAL VELOCITY IS ?? 72?? ? 21.95? ? NOTE THAT THE ACTUAL VELOCITY (VA =21.95) IS ALWAYS LESS THAN THE THEORETICAL VELOCITY (VTH=22.772).
