Explore operational amplifiers in electric circuits with practical examples and applications. Learn about the functionality, analysis, and significance of op-amps in circuit design. Dive into circuits prepared by experts like Dr. Anmar Arif and Dr. Faris Alfaris, discovering insights on node analysis and current flows through components. Understand how op-amps work and their role in circuit configurations. Enhance your knowledge of operational amplifiers with detailed illustrations and explanations.
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Presentation Transcript
EE 202 Electric Circuits Lecture 5 (4-September) First Semester 2023-2024 Dr. Anmar Arif
Op Amp example (1): ??? ??? ????1 ??? ????2: (1) 2 20? ?1 40? ?1+ ?2 = 0 (2) 5 40? ?2 40? ?1+ ?2 = 0 ?2 ?1 ?1 ????1 ? = 0 ?2 ????2 The output current wont enter the loops because there is no way to go back to node b. Therefore, it goes to the ground and return to node b through the ground of the Amp supply. 1
Op Amp example (1): ??? ??? ????1 ??? ????2: (1) 2 20? ?1 40? ?1+ ?2 = 0 (2) 5 40? ?2 40? ?1+ ?2 = 0 ?2 ?1 ?1 ?? ??????? ? ? ????? ???. ?? ???: ????1 ?1= 0.1125 ?? ??? ?2= 0.11875 ?? ? = 0 ?2 ????2 The output current wont enter the loops because there is no way to go back to node b. Therefore, it goes to the ground and return to node b through the ground of the Amp supply. 1
Op Amp example (1): ??? ??? ????1 ??? ????2: (1) 2 20? ?1 40? ?1+ ?2 = 0 (2) 5 40? ?2 40? ?1+ ?2 = 0 ?2 ?1 ?1 ?? ??????? ? ? ????? ???. ?? ???: ????1 ?1= 0.1125 ?? ??? ?2= 0.11875 ?? ? = 0 ??= 2? ?2 ??= 2? 20? 0.1125?? = 0.25 ????2 ?1= ?2= ??= 0.25? ??= 5? ??= ?1= 0.25? The output current wont enter the loops because there is no way to go back to node b. Therefore, it goes to the ground and return to node b through the ground of the Amp supply. ?? 1? ??= ??+ 9? = 2.5? 1
Op Amp example (2): ??????: ?1= ?2 ??? ?1= ?2= 0 From the above conditions: ?2?= 5.8? = ?1? ?2?= 5.8? + 2? = 7.8? = ?1? ?2? Note that voltages drop on ALL 6 is zero because the current through them =0 ? = 0 ? = 0 ?1? ??= ?1?= 7.8? ??? ??= ?1?= 5.8? ?? ?? ?1? ? = 0 ? = 0 ?2? 2
Op Amp example (2): ??????: ?1= ?2 ??? ?1= ?2= 0 From the above conditions: ?2?= 5.8? = ?1? ?2?= 5.8? + 2? = 7.8? = ?1? ?2? Note that voltages drop on ALL 6 is zero because the current through them =0 ? = 0 ? = 0 ?1? ?? ??= ?1?= 7.8? ??? ??= ?1?= 5.8? ?? ??=?? ?? =7.8 5.8 4000 ?? = 0.5 ?? 4000 ?? ??= ??= ??= 0.5 ?? ?? ?1? ? = 0 Again, because all currents through ALL 6 =0 ? = 0 ?2? 2
Op Amp example (2): ??????: ?1= ?2 ??? ?1= ?2= 0 From the above conditions: ?2?= 5.8? = ?1? ?2?= 5.8? + 2? = 7.8? = ?1? ?2? Note that voltages drop on ALL 6 is zero because the current through them =0 ? = 0 ? = 0 ?1? ?? + ??= ?1?= 7.8? ??? ??= ?1?= 5.8? ?? ??=?? ?? =7.8 5.8 4000 ?? = 0.5 ?? ???? 4000 ?? ??= ??= ??= 0.5 ?? ?? ?1? ? = 0 Again, because all currents through ALL 6 =0 ? = 0 ????= ?? 8000 + 4000 + 8000 = 10? ?2? 10 ??= 4000= 2.5 ?? 2
